#$&*
Phy 201
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y components are also equal, but the x and ycomponents of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
• What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
X component = 2 N
Y component = 3 N
Arctan(y component / x component) = arctan (3N / 2N) = 56.3 = 56 N
#$&*
@& 3 N / (2 N) is 1.5. The units divide out.
The arctangent gives you the angle in the units that correspond to the mode of your calculator. In this case you are using degree mode, so the angle is 56 degrees.*@
• What are the components of the equilibrant force?
X component = 2 N
Y component = 3 N
#$&*
• What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
I’m not sure how to solve for the angle of the equilibrant force.
#$&*
*#&!
@&
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
*@