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Phy 201
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
m1 = 60g
v1 = 80 cm/s
m2 = 20g
v2 = 0
1- changes -30cm/s, 2- changes +70cm/s
Yes, the total momentum of the system after collision is the same as the total momentum before the collision. The total momentum stays the same, it is just transferred from one object to another.
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@& It should be so, but according to the given figures it's not quite the same.
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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
I’m not sure how to figure this out. We know that originally the marble is stationary and the steel ball’s velocity is 80cm/s. My guess is that the marble’s velocity would have to be equal to the steel ball’s in order for it to conserve momentum.
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Solution
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