Assignment 22 query

course Mth 152

yfɝᯋefassignment #022

022. `query 22

Liberal Arts Mathematics II

03-24-2008

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21:01:55

**** query 9.3.12 area of parallelogram **** What is the area of the given parallelogram and how did you obtain it?

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RESPONSE -->

A = bh

A = 4(2.5)

A = 10 in^2

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21:02:33

The formula for the area of a parallelogram is

A = bh ( area = base times height)

From the figure the base is 4 and the altitude is 2.5 so we have

A = 4 * 2.5 = 10.

The area is 10 in.

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RESPONSE -->

Correct answer.

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21:19:27

**** query 9.3.18 area of trapezoid **** What is the area of the given trapezoid and how did you obtain it?

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RESPONSE -->

A = 1/2h(b + B)

A = 1/2(3)(4 + 5)

A = 1/2(3)(9)

A = 13.5 cm ^2

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21:19:57

The formula for finding the area of a trapezoid is A = 1/2h ( b + B )

h = 3, b = 4, B = 5

A = 1/2 (3) (4 + 5)

A = 1/2 (3) (9)

A = 1/2 (27)

A = 13.5

The area is 13.5

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RESPONSE -->

Correct answer.

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21:26:14

**** query 9.3.24 dim of rect with lgth 20 more than wdth and perimeter 176 **** What are the dimensions of the rectangle?

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RESPONSE -->

P = 2w + 2l

176 = 2w + 2(w + 20)

176 = 2w + 2w + 40

176 = 4w + 40

176 - 40 = 4w + 40 - 40

136 = 4w

34 = w

w = 34

l = 54

34 + 34 + 54 + 54 = 176

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21:26:31

** The perimeter of a rectangle is P = 2l + 2w, where l and w are length and width.

From the given information

Length = 20 + w

Perimeter = 176

This gives us the equation

176 = 2 (20 + w) + 2w

which we proceed to solve for w:

176 = 40 + 2w + 2w by the Distributive Law. Simplifying we get

176 = 40 + 4w

Subtract 40 from both sides to get

136 = 4w

Divide both sides by 4 to get

w = 34

l = w + 20 so

l = 34 + 20 = 54

We have

Length = 54 and

Width = 34

Checking, we have perimeter = 2 * length + 2 * width so we should have

176 = 2(54) + 2(34).

The right-hand side does give us 176 so the solution checks out. **

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RESPONSE -->

Correct answer.

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22:30:53

**** query 9.3.48 trap bases x, x+4 alt 3 area 30 **** What is the value of x?

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RESPONSE -->

A = 30

A = 1/2h(b + B)

A = 1/2(3)(x + x + 4)

30 = 1.5(2x+4)

30=3x + 6

30-6 = 3x + 6 - 6

24 = 3x

x = 8

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22:31:04

The formula for finding the area of a trapezoid is A = 1/2h ( b + B). We have

A = 30

h = 3

B = x + 4

b = x

30 = 1/2(3) ( x + x+4)

30 = 1.5 ( x+x+4)

30 = 1.5x + 1.5x + 6

30 = 3x + 6 Subtract 6 from both sides

24 = 3x Divide both sides by 3

x = 8

The answer is 8.

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RESPONSE -->

Correct answer.

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22:44:36

**** query 9.3.54 $60 to paint ceiling of 9 x 15 rm, how much to paint if dimensions 18 x 30 **** What is the cost for the second ceiling? **** How did you use the results of exercise 53 to obtain your result?

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RESPONSE -->

9 * 15 = 135 ft. $60/135 = .44

18 * 30 = 540 ft 540 * .44 = $237.60

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22:45:53

The sides doubled from 9 ft. to 18 ft. and from 15 ft. to 30 ft. When the sides are doubled the area increases by a factor of 4. So the cost is

$60 * 4 = $240

The cost for the second ceiling is $240

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RESPONSE -->

I did not use the results from problem #53. I worked the problem out.

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22:48:12

**** query 9.3.60 triangle alt 9 on top of 10 x 4 rect; parallelogram alt 3 under **** What is the area of the given figure and how did you obtain your result?

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RESPONSE -->

A of triangle = 1/2bh

A = 1/2(9)(10) = 45

A of rectangle = l * w

A = 10 * 4 = 40

A of parallelogram = bh

A = 10 * 3 = 30

Area = 45 + 40 + 30 = 115

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22:48:34

** Here's a solution by a student from a previous semester:

I found the area of each figure and then added those three results together.

Area of Triangle = 1/2bh

A = 1/2 (10) (9)

A = 1/2 (90)

A = 45

Area of Rectangle = lw

A = (10) (4)

A = 40

Area of Parallelogram = bh

A = (10) (3)

A = 30

45 + 40 + 30 = 115

Area = 115 **

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RESPONSE -->

Correct answer.

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22:54:11

**** query 9.3.67 26 m diam circle inscribed in sq; area outside circle **** What is the area of the shaded region and how did you obtain it?

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RESPONSE -->

A of the square = s^2

A = 26^2 = 676

A of the circle = pi (r)^2

A = 3.14 (13)^2 = 3.14(169)=530.66

676 - 530.66 = 145.34 m^2 (area of shaded region)

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22:54:26

** The circle has diameter 26 m so its radius is 13 m and its area is

A = pi r^2 = pi * (13 m)^2 = 169 pi m^2 = 531 m^2.

The area of the square is the square of its side

A = (26 m)^2 = 676 m^2.

The area of the shaded region is the difference

}

676 m^2 - 531 m^2 = 145 m^2. **

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RESPONSE -->

Correct answer.

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22:58:09

**** query 9.3.72 10, 12, 14 in pizzas for 11.99, 13.99, 14.99 **** Which pizza is the best buy and how did you

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RESPONSE -->

3.14(5)^2 = 78.5; $11.99/78.5 = .15

3.14(6)^2 = 113.04; $13.99/113.04 = .12

3.14(7)^2 = 153.86; $14.99/153.86 = .10

14-inch pizza for $14.99 is the best buy.

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22:58:29

obtain your result?

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RESPONSE -->

14-inch pizza for $14.99 is the best buy.

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22:58:50

Student Solution: The thickness is about the same for all three pizzas so the amount of pizza can be measured by its area. I therefore found the area of each.

A = 3.14 * r^2 and radius is 1/2 the circumference. So we get areas

A = 3.14 (5)^2 = 78.5

A = 3.14 (6)^2 = 113.04

A = 3.14 (7)^2 = 153.86

I then divide the prices and these answers to get the price per square inch.

$11.99 / 78.5 = 15.3

$13.99 / 113.04 = 12.4

$14.99 / 153.86 = 9.7

Since 9.7 is the least, and since this is the result for the 14 inch pizza, the 14 in. pizza for $14.99 is the best buy.

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RESPONSE -->

Correct answer.

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22:58:57

**** Query Add comments on any surprises or insights you experienced as a result of this assignment.

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RESPONSE -->

No surprises.

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Very good work. Let me know if you have questions. &#