Introductory Questions

course Phy 121

5/13 10:35am

Introductory Question-Answer (qa) Sequence

You have probably submitted your answers the first two questions in a preceding task. You are welcome to answer them again, but if you have already submitted them you may go ahead and skip to the third question.

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Question: `q003.

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Your solution:

$72/$8 per hour = 9 hours (dollars cancels out). If we make $8 an hour, we would add up $8 until we reach $72. We can also divide $72 by the dollars per hour to get hours.

confidence rating #$&*

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Self-critique (if necessary): OK

Self-critique rating #$&* OK

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Question: `q004.

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Your solution:

(8 + 3) * 5 = (11)*5 = 55

8 + 3 * 5 = 8 + 15 = 23

We get different answers because we have to follow the order of operations.

Confidence rating #$&* 3

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q005.

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Your solution:

(2^4) * 3 = (16)*3 = 48

2^(4 * 3) = 2^(12) = 4096

confidence rating #$&*

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Given Solution:

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q006.

Your solution:

3 * 5 - 4 * 3 ^ 2 = 15 – 4*9 = 15 – 36 = -21

3 * 5 - (4 * 3)^2 = 15 – (12)^2 = 15 – 144 = 129

confidence rating #$&*

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q007.

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Your solution:

y = 2 x + 3 = 2(-2) + 3 = -4 + 3 = -1

(-2,-1), (-1,1), (0,3), (1,5), (2,7)

My graph goes through the points listed earlier in the solution, and it makes a line.

confidence rating #$&*

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q008.

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Your solution:

y = x^2 + 3 = (-2)^2 + 3 = 4 + 3 = 7

(-2,7), (-1,4), (0,3), (1,4) (2,7)

The graph shows an upward facing U-shape (symmetrical about the y-axis), so we can determine that the graph is quadratic. This makes sense, since we have an exponent for our x variable.

confidence rating #$&*

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q009

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Your solution:

When x = 1, y = 2^x + 3 = 2^1 + 3 = 2 + 3 =5 (follow order of operations)

(1, 5), (2, 7), (3, 11), (4, 19)

The value for y is increasing larger and larger for each increase in x on the graph, so we have an exponential graph

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When x = 1, we obtain y = 2^1 + 3 = 2 + 3 = 5.

“ x = 2 we obtain y = 2^2 + 3 = 4 + 3 = 7.

“ x = 3 we obtain y = 2^3 + 3 = 8 + 3 = 11.

“ x = 4 we obtain y = 2^4 + 3 = 16 + 3 = 19.

(1, 5), (2, 7), (3, 11), (4, 19)

confidence rating #$&*

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q010.

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Your solution:

It is equal to the original number because any number divided by one remains the same. EX: 25/1 = 25 and 8.95/1 = 8.95

confidence rating #$&*

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q011.

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Your solution:

The result is always less than the original number. EX: 30/5 = 6 and 30/6 = 5 and 100/2 = 50

confidence rating #$&*

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q012.

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Your solution:

The result will be greater than the original. EX: 5/0.5 = 10

confidence rating #$&*

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Self-critique (if necessary): OK

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Self-critique rating #$&* OK

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Question: `q013.

your answer: vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

When x = 1, y = 2^x + 3 = 2^1 + 3 = 2 + 3 =5 (follow order of operations)

(1, 5), (2, 7), (3, 11), (4, 19)

The value for y is increasing larger and larger for each increase in x on the graph, so we have an exponential graph

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When x = 1, we obtain y = 2^1 + 3 = 2 + 3 = 5.

“ x = 2 we obtain y = 2^2 + 3 = 4 + 3 = 7.

“ x = 3 we obtain y = 2^3 + 3 = 8 + 3 = 11.

“ x = 4 we obtain y = 2^4 + 3 = 16 + 3 = 19.

(1, 5), (2, 7), (3, 11), (4, 19)

Introductory Questions

&#Good responses. Let me know if you have questions. &#