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Phy 121
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_06.1_labelMessages **
For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.
• A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> :
Given: v0 = 10cm/s, vf = 20cm/s, ‘ds = 45cm
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• A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> :
Given: a = 10cm/s^2, ‘dt = 3s, vf = 50cm/s
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• A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> :
Given: ‘ds = 30cm, v0 = 0cm/s, a = 20cm/s^2
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Then for each situation answer the following:
• Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> :
Situation 1:
vAve = (vf +v0)/2, yes we can find vAve. We are given v0 and vf.
vAve = (20cm/s + 10cm/s)/2 = (30cm/s)/2 = 15cm/s
Situation 2:
vAve = (vf +v0)/2, no we can not find directly. We don’t have v0 or ‘dt for vAve = ‘ds/’dt.
Yes, we can find using the uniform accel equations.
Situation 3:
vAve = (vf +v0)/2 or from rest vf = 2*vAve, no we can not find directly. We don’t have vf
Yes, we can find using the uniform accel equations.
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• Is it possible to directly determine `dv?
answer/question/discussion: ->->->->->->->->->->->-> :
Situation 1:
Given: v0 = 10cm/s, vf = 20cm/s, ‘ds = 45cm
Find ‘dv. ‘dv = vf - v0, yes we can find directly. We have vf and v0
Situation 2:
Given: a = 10cm/s^2, ‘dt = 3s, vf = 50cm/s
Find ‘dv. ‘dv = vf - v0, no we can not find directly.
Yes we can find using uniform accel equations.
Situation 3:
Given: ‘ds = 30cm, v0 = 0cm/s, a = 20cm/s^2
Find ‘dv. ‘dv = vf - v0, no we can not find directly.
Yes we can find using uniform accel equations.
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*#&!
&#Very good responses. Let me know if you have questions. &#