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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Newtons Second Law is a=Fnet/m
Fnet=ma=12kg * 3m/s^2 = 36kg*m/s^2 = 36N
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a=Fnet/m = 20N/4kg = (20kg*m/s^2)/4kg = 5m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
a=Fnet/m=20N/10kg=2m/s^2
So, to be at an actual a of 1.5m/s^2, some other force is in the equation, assuming the mass is correct.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
Direction of my force is positive.
F1=20N*10kg=2m/s^2
F2=(1.5m/s^2 - 2m/s^2)*10kg=-5N
Fnet= F1 + F2 = 20N - 5N = 15N
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Copy and paste your work into the box below and submit as indicated:
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30 minutes
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&#Very good responses. Let me know if you have questions. &#