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Assignment 12 Seed Question 1
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: The net force in the problem would be equal to Fnet= m1*a1 – m2 * a2 = 5kg * 9.8 m/s^2 – 6kg * 9.8 m/s^2 = -9.8N. The direction is in the direction of the heavier mass, which was 6 kg. Gravity is pulling it downwards.
Good, but you still need to find the magnitude of the acceleration of the system.
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: If this were the case, we would need a new force of acceleration to multiply the 5kg mass by. We would then have the equation Fnet=(5kg)(1.8m/s/s+9.8m/s/s)-(6kg)(9.8m/s/s)=58N-5.8N= -8N. It is still moving in a downward direction toward the 6kg side, because of the force of gravity.
You are given an initial speed of 1.8 meters/second. This is not an acceleration. This speed is at the instant of release. After release only the gravitational forces are acting, and the net force on the system is still -9.8 N.
The acceleration is therefore the same as in the first question. You have been given the initial speed and the time interval. What is the velocity at the end of the 1-second time interval?
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: The velocity and the acceleration are moving in opposite directions, because the system is set up in a pulley style. After the push, the system will continually slow down, as gravity acts on the force and will gradually bring the system to a rest.
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This assignment took me approximately 10 minutes.
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