cq_1_192

Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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Assignment 19 Seed Question 2

Sketch a vector representing a 10 Newton force which acts vertically downward.

• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.

• What are the x and y components of the equilibrant of the force?

answer/question/discussion: To find the x and y components of the equilibrant force, we use the equations vx = v sin (theta) and the equation vy = v sin (theta). For the vx value, we get vx = 10 N * cos (250 degrees) = 10 N * -0.34) = -34 N. For the vy value, we get vy = 10 N * sin (250 degrees) = 10 N * -0.94 = -94 N.

Calculations are right, but I believe you get -3.4 N and -9.4 N, not -34 N and -94 N. The latter result don't make sense on the scale of the given force.

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It took me about 15 minutes to do the work for this question.

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&#This looks good. See my notes. Let me know if you have any questions. &#