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PHY 201
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_24.2_labelMessages **
A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec. •Is the total momentum of the system after collision the same as the total momentum before?
.06kg * .5m/s + .02kg * .7m/s=.03kg*m/s + .014kg*m/s =.044kg*m/s
answer/question/discussion: ->->->->->->->->->->->-> :
• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
60g .048kg*m/s -.03kg*m/s=.018kg*m/s so .02kg*v_marble=.018kg*m/s which =.018kg m/s / .02kg =.9m/s
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