cq_1_222

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PHY 121

Your 'cq_1_22.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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A 70 gram ball rolls off the edge of a table and falls freely to the floor 122 cm below. While in free fall it moves 40 cm in the horizontal direction. At the instant it leaves the edge it is moving only in the horizontal direction. In the vertical direction, at this instant it is moving neither up nor down so its vertical velocity is zero. For the interval of free fall:

• What are its final velocity in the vertical direction and its average velocity in the horizontal direction?

answer/question/discussion: ->->->->->->->->->->->-> :

a=9.8m/s/s.

ds=.122m,

v0=0m/s.

vf^2=v0^2+2ads = 0+2(9.8m/s/s)(.122m) = 2.4m^2/s^2, vf= 1.5m/s.

ave vel=(v0+vf)/2 = (1.5m/s + 0m/s)/2 = .75m/s.

.75m/s = .122m/dt,

dt = .122m/.75m/s = .2s

.040m/.2s = .2m/s.

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Good, if the fall is .122 m and the horizontal displacement is .040 m.

However 122 cm is 1.22 m, and 40 cm is .40 m.

No need to resubmit, but make a note of your conversion error.

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