Assignment-10

course Mth163

submitted Sunday, June 28, 2009 at 6:45.I have had some unfortunate events happen this week which has put me very behind. I will try to get one more assignment turned in, but I may not get both done tonight.

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

I hope everything is OK. Catch up gradually.

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

010.

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

Self-critique Rating:

*********************************************

Question: `q001. Note that this assignment has 10 questions

Sketch the function y = x and describe your graph. Describe how the graphs of y = .5 x and y = 2 x compare with the graph of y = x.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

y = .5x is ½ of each point of x = y putting it closer to the x axis, also the coordinates (0,0) are the same on both functions.

y = 2x is 2 units greater each point than the y = x function with the exception of (0,0), which is the same on both functions. This line also moves closer to the y axis and further a way from the x.

Confidence Assessment: mostly

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

The graph of y = x consists of a straight line through the origin, having slope 1. This line has basic points (0,0) and (1,1).

The points of the graph of y = .5 x all lie twice as close to the x-axis as the points of the graph of y = x. The point (0,0) of the y = x graph is already on the x-axis, so the corresponding point on the graph of y = .5 x is also (0,0). The point (1,1) of the y = x graph lies 1 unit above the x-axis, so the corresponding point on the graph of y = .5 x will lie twice as close, or .5 units above the x-axis, so that the corresponding point is (1, .5). The graph of y = .5 x Thus passes through the points (0,0) and (1,.5).

Of course this result could have been found by simply plugging 0 and 1 into the function y = .5 x, but the point here is to see that we can get the same result if we think of moving all points twice as close. This order thinking will be useful when dealing with more complex functions.

Thinking along similar lines we expect the points of the graph of y = 2 x to all lie twice as far from the x-axis as the points of the function y = x. Thus the two basic points (0,0) and (1,1) of the y = x graph will correspond to the points (0,0) and (1,2) on the graph of y = 2 x.

Assignment-10

I hope everything is OK. Catch up gradually.

Maybe easier to understand if we work backwards: -1.77 * (x2 - x1) = -1.77 * x2 - (-1.77 * x1) = -1.77 x2 + 1.77 x1, which is the same thing as 1.77 x1 - 1.77 x2. -1.77 * (x2 - x1) was chosen as the form, so we could easily divide it by x2 - x1.

If you send me the name of your calculator and a copy of these few lines I'll tell you where to look for instructions. It's worth knowing. However this isn't something you'll need to do on a test.

The student's two equations were somewhat different; however the difference is in the range of uncertainty for the quantities being observed.

&#Good responses. See my notes and let me know if you have questions. &#

Maybe easier to understand if we work backwards:

-1.77 * (x2 - x1) = -1.77 * x2 - (-1.77 * x1) = -1.77 x2 + 1.77 x1, which is the same thing as 1.77 x1 - 1.77 x2.

-1.77 * (x2 - x1) was chosen as the form, so we could easily divide it by x2 - x1.

If you send me the name of your calculator and a copy of these few lines I'll tell you where to look for instructions.

It's worth knowing. However this isn't something you'll need to do on a test.