course Mth163
If your solution to stated problem does not match the given solution, you should self-critique per instructions at
http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.
Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.
019. `query 19
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Question: `qexplain the steps in fitting an exponential function to data
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Your solution:
First you have to take a set of data points and see if they are a perfect or exponential data.
Next we take the log of the original y data.
Then we sketch a graph with our data points and draw a best fit straight line.
We can use DERIVE or pick two points and figure out slope and the y intercept.
Then we put it into an equation of log y = Ax + b and solve by taking the log(which is 10^) of both sides and receiving your model.
Now you can take your model and solve for your y values of your original x values.
Confidence rating: mostly
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Given Solution:
`a** If you have two points you can solve the simultaneous equations. If you have a more extensive data set you use
transformations.
For exponential data you plot log(y) vs. x. If the graph is a straight line then you have a good fit.
If the slope is m and the vertical intercept is b then your graph gives you log(y) = m x + b.
You invert the transformation using the inverse function 10^x, obtaining 10^log(y) = 10^(mx+b) so that
y = 10^(mx) * 10^b, and then rearrange this into the desired form.
Note that if a power function fits the data then log y vs. log x will give a straight line so that log y = m log x + b. In this
case our solution will be y = 10^b * x^m, a power function rather than an exponential function. **
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Self-critique (if necessary):
Ok, if data points is already given you take and make 2 models in the form of y = A b^x and divide the first one by the second one and then solve for b. Then you plug that in to solve for A and you have your model.
Self-critique rating:
ok
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&#This looks very good. Let me know if you have any questions. &#