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Phy 241
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_04.1_labelMessages **
The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
Sketch a straight line segment between these points.
What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
rise: 40 cm/s - 10 cm/s = 30 cm/s
Run: 9 s - 4 s = 4 sec
Slope: 30 cm/s / 4 sec = 15 cm/s / 2 sec or 7.5 cm/sec^2
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Good, but 9 s - 4 s = 5 s, not 4 s. So the slope sould be 6 cm/s^2.
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What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> scussion (start in the next line):
Area of a trapezoid = 1/2 * b * (h1 + h2)
area = 0.5 * 5 seconds * (10 cm/s + 40 cm/s)
area = 125 cm
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20 min
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&#Good responses. See my notes and let me know if you have questions. &#