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course Phy 121
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest. At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion:
a=dv/(change in slope)
dv=(10m/5s)-(10m/8s)=(2m/s)-(1.25m/s)=.75m/s
change in slope= .1-.05=.05
a=(.75m/s)/(.05units)=15m/s/unit
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(10m/5s)-(10m/8s) is the difference in the velocities for the two trials. So your result is the rate at which the average velocity changes with respect to slope. A good try, but not quite what was requested.
We are looking for the rate at which the acceleration changes with respect to slope. So you need to start by calculating the acceleration on each incline.
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