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Phy 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Force of 5kg side:
F=5kg*9.8m/s^2
F=49N
Force of 6kg Side
F=6kg*9.8m/s^2
F=58.8N
Fnet=58.8N-49N
Fnet=9.8N
Acceleration:
9.8N=11kg*a
a=.89m/s^2 this would be in the direction of the 6kg side
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
Since this is a frictionless pulley, the net force will be the same in either direction, but the acceleration would be resisting the direction of motion so is would be negative.
A=-.89m/s^2
v0=1.8m/s
dt=1s
vf=v0+a*dt
vf=1.8m/s+(-.89m/s^2)(1s)
vf=.91m/s
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
During the first second the velocity and acceleration are opposing each other, and as a result the system will slow down.
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&#Very good responses. Let me know if you have questions. &#