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course Phy 121
A child in a car tosses a ball upward so that after release it requires 1/2 second to rise and fall back into the child's hand at the same height from which it was released. The car is traveling at a constant speed of 10 meters / second in the horizontal direction. Between release and catch, how far did the ball travel in the horizontal direction?
answer/question/discussion:
(10m/s)*(1/2s)=5m
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As observed by a passenger in the car, what was the path of the ball from its release until the instant it was caught?
answer/question/discussion:
It would rise strait up and fall strait down.
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Sketch the path of the ball as observed by a line of people standing along the side of the road. Describe your sketch. What was shape of the path of the ball?
answer/question/discussion:
It would have made a upside down parabola shaped arc
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How fast was the ball moving in the vertical direction at the instant of release? At that instant, what is its velocity as observed by a line of people standing along the side of the road?
answer/question/discussion:
vf=v0+a*dt
0m/s=v0+-9.8m/s^2*.5s
v0=4.9m/s
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How high did the ball rise above its point of release before it began to fall back down?
answer/question/discussion:
vf^2=v0^2+2*a*ds
(0m/s)^2=(4.9m/s)^2+2*-9.8m/s^2*ds
ds=1.23m
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&#Very good work. Let me know if you have questions. &#
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Quick note: You appear to have provided a password different from your access code. It's no problem for me to correct an occasional glitch of this kind. My bigger concern is that this is an important password to something, in which case I just want to caution you about using it only where and when it's appropriate.
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