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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
· Based on this information what is its acceleration?
answer/question/discussion: vAve = 2m/.64s = 3.125m/s. The final velocity is 2 * vAve = 6.25m/s. Since the ball started from rest, the velocity change is 6.25m/s. a = ‘dv / ‘dt = 6.25m/s / .64s = 9.77m/s/s
· Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: No, the vAve is 4.76 m/s. The final velocity is 9.52s. The a = 9.52m/s / 1.05s = 9.07m/s/s
· Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: No, the first one could be rounded to get 9.8m/s/s but the second one could only be 9.1 m/s/s.
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15 min
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&#This looks very good. Let me know if you have any questions. &#