course phy 201
Good work.
Let me know if anything is unclear, and include specifics about what you do and do not understand.
1. By finding the average velocity and then over the time period that it is graphed. This will give you the area and this is how we calculate a position change. 2. The displacement is always equal to the average velocity multiplied by the time interval. You have to find the change in position over the time intervals. You find the change in position by multiplying the velocity for each section by the time interval. Then you find the displacement by starting with zero and adding the change in position to each other. Which is the cumulated area under the graph. You then plot these
3. By multiplying the average velocity, average height, by the time interval, width, we get the position change which is also the area.
4. Use the areas from the velocity vs time graph to get the areas to obtain a position vs time graph and use the slopes of this position vs time graph to get back to the velocities we started with.
Experiment.
With the graph having an upward curve it shows that it takes more time to the first couple on cm and then more distance is covered in the same amount of time. In the graph above at 1s the displacement was 1m, at 2s the displacement was 4m, at 3s the displacement was 9m and then finally at 4s the displacement was 16m. As you can see as more time went by more distance was covered per second compared to the being 2 seconds.