course phy 201
......!!!!!!!!...................................
00:45:16 Given the initial velocity, final velocity and time duration of a uniformly accelerating object, how do we reason out the corresponding acceleration and change in the position of an object?
......!!!!!!!!...................................
RESPONSE --> First you have to find the total displacement which is when we multiply the average velocity by the timer interval. Then you can find the average velocity is the average of the initial and final velocity. We then get the displacement by multiplying the average velocity by the time interval. You then can find the acceleration. which we divide the change in velocity by the time intreval. You can then find the change in poistion of an object by multplying the average velocity over the intreval of duration of the interval.
.................................................
......!!!!!!!!...................................
00:47:15 ** COMMON ERRONEOUS STUDENT RESPONSE: To find the average acceleration, we divide the change in veolocity by the time interval. To find the change in position or displacement of the object over any time interval multiply the average velocity over that interval by the duration of the interval. You are not given the average velocity or the change in velocity. You have to first determine the average velocity; then your strategy will work. Since acceleration is constant you can say that average velocity is the average of initial and final velocities: vAve = (v0 + vf) / 2. Change in velocity is `dv = vf - v0. Now we can do as you say: To find the change in position or displacement of the object over any time interval multiply the average velocity over that interval by the duration of the interval. **
......!!!!!!!!...................................
RESPONSE --> I thought tah tI said you need to find the average velocity in my answere?
.................................................
......!!!!!!!!...................................
00:51:47 In terms of the meanings of altitudes, area, slope and width, how does a velocity vs. clock time trapezoid represent change in position and acceleration?
......!!!!!!!!...................................
RESPONSE --> The vertical direction represents velocity and tehe horizontal direction represents clock time. The slope ( rise/run) (the change in velocity / time duration) represents the time rate of change of the velocity which is also the acceleration. By multiplying the average altitude by the width of the trap, which is average velocity by the time duration we get the change of posititon.
.................................................
......!!!!!!!!...................................
00:52:08 ** If you multiply the average altitude by the width (finding the area) of the trapezoid you are multiplying the average velocity by the time interval. This gives you the displacement during the time interval. The rise of the triangle represents the change in velocity and the run represents the time interval, so slope = rise / run represents change in velocity / time interval = acceleration. **
......!!!!!!!!...................................
RESPONSE --> right
.................................................