course phy 201
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Week 3 Quiz 2 Version
Determine the acceleration of an object whose velocity is initially 24 cm/s and which accelerates uniformly through a distance of 66 cm in 3.8 s
The initial velocity is 24 cm/s
You find the final velocity by dividing the displacement by the time interval
66cm/3.8s = 17.4cm/s
Average velocity is displacement / time interval. Unless velocity is constant, final velocity will not equal average velocity.
The acceleration is the change in velocity/change in time interval
a = (17.4cm/s-24cm/s) / 3.8second = -1.74cm/s^2
Once you have the correct final velocity, this is the correct process.
You actually calculated average velocity but called in final velocity.
See my note and please send me a revision, and/or questions if it's not clear what you need to do.