Your work on torques has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Positions of the three points of application, lengths of systems B, A and C (left to right), the forces in Newtons exerted by those systems, description of the reference point:
0,6.7,12.6
9.8,9.7,10.02
1.52,1.14,1.7
B
found the lengths then went to the graphs and obtained the info from that
Net force and net force as a percent of the sum of the magnitudes of all forces:
+9.48
32.1
Moment arms for rubber band systems A and C
6.71
5.98
Lengths in cm of force vectors in 4 cm to 1 N scale drawing, distances from the fulcrum to points B and C.
6.08,4.56,6.8
6.71,5.98
Torque produced by B, torque produced by C:
+40.7968
-40.664
Net torque, net torque as percent of the sum of the magnitudes of the torques:
0.1328
0.16
added the torques and got first number then subtracted then from each other and then took the net and divided by the subtracted number they multiplied by 100
Forces, distances from equilibrium and torques exerted by A, B, C, D:
1.8,0,0,
1.6,4.3,-6.88
1,11,-11
0.42,13.5,5.67
The sum of the vertical forces on the rod, and your discussion of the extent to which your picture fails to accurately describe the forces:
-0.38
yes because the rod should be down a little
Net torque for given picture; your discussion of whether this figure could be accurate for a stationary rod:
6
gravity is acting on the rod
For first setup: Sum of torques for your setup; magnitude of resultant and sum of magnitudes of forces; magnitude of resultant as percent of sum of magnitudes of forces; magnitude of resultant torque, sum of magnitudes of torques, magnitude of resultant torque as percent of the sum of the magnitudes:
-12.21
-1.18,4.82
24
-12.21,23.55,52
For second setup: Sum of torques for your setup; magnitude of resultant and sum of magnitudes of forces; magnitude of resultant as percent of sum of magnitudes of forces; magnitude of resultant torque, sum of magnitudes of torques, magnitude of resultant torque as percent of the sum of the magnitudes:
-17.62
-0.9,6.3
14
5.67,23.765,24
In the second setup, were the forces all parallel to one another?
I would say they are off by 5 degrees
Estimated angles of the four forces; short discussion of accuracy of estimates.
90,89,87,85
i think that they are farely accurate
x and y coordinates of both ends of each rubber band, in cm
7.2,-11,7.2,-1.5
0.7,0.9,0.5,10.5
5.6,-1.2,9.2,-11.5
Lengths and forces exerted systems B, A and C:.
9.5,1
9.6,1.1
10.9,2.2
used the pythagoream theorem and then the graph calibration
Sines and cosines of systems B, A and C:
0,1
0.02,-1.2
-0.33,-0.94
Magnitude, angle with horizontal and angle in the plane for each force:
1,0,
1.2,270,
2.2,71
first answer form abover secodn answer arctan of the ya nd v from above
x and y components of sketch, x and y components of force from sketch components, x and y components from magnitude, sine and cosine (lines in order B, A, C):
0,4,0,1.5,0,9.5
1.1,4.4,0.275,1.1,0,9.6
1.9,8.8,0.475,2.2,3.5,10.3
Sum of x components, ideal sum, how close are you to the ideal; then the same for y components.
3.5,3.0, 0.5
29.4,20.13,9.27
Distance of the point of action from that of the leftmost force, component perpendicular to the rod, and torque for each force:
0,9.5,0
7.9,9.6,+75.84
14.1,10.9,-153.69
Sum of torques, ideal sum, how close are you to the ideal.
-77.85,?
How long did it take you to complete this experiment?
hours
Optional additional comments and/or questions:
Didn't know how to do some of the things
h3>Ideally the sum of the torques and the sum of the forces in each direction should be 0. Calibration errors and other errors can introduce a significant amount of uncertainty into the results of this experiment.
Your calculations look good.