R1

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course mth 151

1/26/11 around 17:15

If your solution to stated problem does not match the given solution, you should self-critique per instructions at http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.

Your solution, attempt at solution:

If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

001. `* 1

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Question: * R.1.26 \ was R.1.14 (was R.1.6) Of the numbers in the set {-sqrt(2), pi + sqrt(2), 1 / 2 + 10.3} which are counting numbers, which are rational numbers, which are irrational numbers and which are real numbers?

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Your solution:

None are counting numbers , none are integers as integers must be whole numbers with + or – sign in front of them. 1 / 2 + 10.3 is rational and -sqrt(2), pi + sqrt(2) is irrational. The numbers continue in a Radom pattern instead of a repeated value like with rational numbers.

confidence rating #$&*: 3

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Given Solution:

* * ** Counting numbers are the numbers 1, 2, 3, .... . None of the given numbers are counting numbers

Rational numbers are numbers which can be expressed as the ratio of two integers. 1/2+10.3 are rational numbers.

Irrational numbers are numbers which can be expressed as the ratio of two integers. {-sqrt(2)}, pi+sqrt(2) are irrational numbers.. **

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Self-critique (if necessary): Ok

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Self-critique Rating:

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Question: * R.1.44 \ 32 (was R.1.24) Write in symbols: The product of 2 and x is the product of 4 and 6

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Your solution:

2x = 4*6

confidence rating #$&*: 3

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Given Solution:

* * ** The product of 2 and x is 2 * x and the product of 4 and 6 is 4 * 6. To say that these are identical is to say that 2*x=4*6. **

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Self-critique (if necessary): ok

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Self-critique Rating:

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Question:

* R.1.62 \ 50 (was R.1.42) Explain how you evaluate the expression 2 - 5 * 4 - [ 6 * ( 3 - 4) ]

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Your solution:

2-5*4-[6*(3-4)] I got to remember PEMDAS

P: 2 – 5 * 4 – [6 * ( 3 – 4 )]

P: 2 – 5 * 4 – [6 *( - 1) ]

P: 2 – 5 * 4 – [ - 6 ]

No Exponents

M or D: 2 – 5 * 4 – [ - 6 ]

M or D: 2 – 20 – [ - 6 ]

A or S : 2 – 20 + 6

A or S : - 18 + 6

Answer : - 12

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Self-critique Rating: ok I need to remember that 2 -20 = -18 not - 22

confidence rating #$&*: 2

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Given Solution:

* * **Starting with

2-5*4-[6*(3-4)]. First you evaluate the innermost group to get

2-5*4-[6*-1] . Then multiply inside brackets to get

2-5*4+6. Then do the multiplication to get

2-20+6. Then add and subtract in order, obtaining

-12. **

* R.1.98 \ 80 (was R.1.72) Explain how you use the distributive property to remove the parentheses from the express (x-2)(x-4).

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Your solution:

Use the FOIL method First Outer Inter Last

F: X ^2

O:- 4X

I: -2 x

L: 8

Combine like terms: x^2 + 2X-4x + 8

Answer: X^2 -6X +8

confidence rating #$&*: 3

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Given Solution:

* * ** COMMON ERROR: Using FOIL. FOIL is not the Distributive Law. FOIL works for binomial expressions. FOIL follows from the distributive law but is of extremely limited usefulness and the instructor does not recommend relying on FOIL.

Starting with

(x-2)(x-4) ; one application of the Distributive Property gives you

x(x-4) - 2(x-4) . Applying the property to both of the other terms we get

x^2 - 4x - (2x -8). Simplifying:

x^2 - 4x - 2x + 8 or

x^2 - 6x + 8. *

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Self-critique (if necessary): Ok I this instance I could use the FOIL because it a binominal times a binominal. I also need to work on my addition with negative numbers.

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Self-critique Rating:ok

@& This was to be done using the distributive law, not FOIL.

Be sure you understand how to do this with the distributive law. There are many, many problems that FOIL doesn't work with.*@

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Question:

* R.1.102 \ 86 (was R.1.78) Explain why (4+3) / (2+5) is not equal to 4/2 + 3/5.

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Your solution:

(4+3)/(2+5)= 4/2 + 3/5 =

(7)/(7)= 1 must find the same denominator

4/2 = 20/10 3/5 = 26/10

Solve

26/10 =13/5

1 does not equal 13/5 or 2/2/3.

With the parentheses you must add first (pemdas) so in (4+3)/(2

confidence rating #$&*: 3

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Question:

* R.1.102 \ 86 (was R.1.78) Explain why (4+3) / (2+5) is not equal to 4/2 + 3/5.

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Your solution:

(4+3)/(2+5)= 4/2 + 3/5 =

(7)/(7)= 1 must find the same denominator

4/2 = 20/10 3/5 = 26/10

Solve

26/10 =13/5

1 does not equal 13/5 or 2/2/3.

With the parentheses you must add first (pemdas) so in (4+3)/(2

confidence rating #$&*: 3

#(*!

&#This looks good. See my notes. Let me know if you have any questions. &#