course 231
2/12; 1:10pm
Experiment:•How does the shape of the corresponding position vs. clock time graph, with its upward curvature, show us that the time required to travel the first half of the incline is greater than that required to travel the second half?
Due to the upward curve, were allowed more area underneath it, which represents displacement. With a higher curve, the time interval needed to cover the same amount of area(distance traveled) is smaller the second time.
Problems:
• Given the constant rate at which velocity changes, initial velocity, and time duration, how do we reason out the corresponding change in the position of an object?
First, you multiply the rate at which velocity changes and time duration, then add the initial velocity. Now we can solve for average velocity by adding final and initial velocity and dividing by two. Now that we have average velocity, we can multiply that by time to find the total disposition.
• How do we determine position changes over specified time intervals from a graph of velocity vs. clock time, and how can we then construct a graph of position vs. clock time?
By finding the area underneath the function, we can determine the total displacement.
• In terms of the meanings of altitudes, area and width, how does a velocity vs. clock time trapezoid represent change in position?
The area of the trapezoid is the change in position.
• How can a series of velocity vs. clock time trapezoids help us to calculate and visualize position vs. clock time information?
You can calculate velocity and acceleration from the slope of the graph.
&#Good responses. Let me know if you have questions. &#