course Mth 158 jŧٴoassignment #001
......!!!!!!!!...................................
08:35:39 `q001. Part 1 includes six activities. If you have completed an activity, just enter the answer 'completed'. This question is appearing in the Question box. The box to the right is the Answer box, where you will type in your answers to the questions posed here. To use this program you read a question, then enter your answer in the Answer box and click on Enter Answer. In your answers give what is requested, but don't go into excruciating detail. Try to give just enough that the instructor can tell that you understand an item. After entering an answer click on Next Question/Answer above the Question box. Do you understand these instructions?
......!!!!!!!!...................................
RESPONSE -->
.................................................
......!!!!!!!!...................................
08:37:35 This program has created the folder c:\vhmthphy on your hard drive. Browse to that folder and locate the file whose name begins with SEND. The name of this file will also include your name, as you gave it to the program, and the file will show as a Text file. Never tamper with a SEND file in any way. It contains internal codes as if these codes are tampered with you won't get credit for the assignment. However you are welcome to copy this file to another location and view it, make changes, etc. Just be sure that when requested to do so you send the instructor the original, tamper-free file. State in the Answer box whether or not you have been able to locate the SEND file. Don't send the SEND file yet. Note that more questions/instructions remain in the q_a_prelim.
......!!!!!!!!...................................
RESPONSE --> i have found the SEND file
.................................................
......!!!!!!!!...................................
08:39:54 `q002. Note that every time you click on Enter Answer the program writes your response to your SEND file. Even if the program disappears all the information you have entered with the Enter Answer button will remain in that file. This program never 'unwrites' anything. Even if this program crashes your information will still be there in the SEND file. Explain this in your own words.
......!!!!!!!!...................................
RESPONSE --> When you respond and click on enter response the program puts your response in your SEND file. If the program disappears the information you have entered using the enter response button will stay in that file.
.................................................
......!!!!!!!!...................................
08:40:27 Any time the instructor does not post a response to your access site by the end of the following day, you should resubmit your work using the Submit Work form, and be sure at the beginning to indicate that you are resubmitting, and also indicate the date on which you originally submitted your work. If you don't know where your access site is or how to access it, go to http://www.vhcc.edu/dsmith/_vti_bin/shtml.dll/request_access_code.htm and request one now. You can submit the q_a_prelim without your access code, but other assignments should contain your code.
......!!!!!!!!...................................
RESPONSE --> OK
.................................................
......!!!!!!!!...................................
08:40:44 `q003. If you are working on a VHCC computer, it is probably set up in such a way as to return to its original configuration when it is rebooted. To avoid losing information it is suggested that you back up your work frequently, either by emailing yourself a copy or by using a key drive or other device. This is a good idea on any computer. Please indicate your understanding of this suggestion.
......!!!!!!!!...................................
RESPONSE --> OK
.................................................
ͼ\xVϿz͜ZG assignment #001 001. typewriter notation qa initial problems 05-24-2007
......!!!!!!!!...................................
09:43:55 `q001. Explain the difference between x - 2 / x + 4 and (x - 2) / (x + 4). The evaluate each expression for x = 2.
......!!!!!!!!...................................
RESPONSE --> in x - 2 / x + 4 you would divide 2 by x then x - 2 /x and finally add 4. In the problem (x - 2) / (x - 4) you would do everything in the parentheses first then divide the answers x - 2 / x + 4 = (x - 2) / (x + 4) 2 - 2 / 2 + 4 (2 - 2) / (2 + 4) 2 - 1 + 4 0 / 6= 0 1+ 4 = 5 confidence assessment: 2
.................................................
......!!!!!!!!...................................
09:46:25 `q002. Explain the difference between 2 ^ x + 4 and 2 ^ (x + 4). Then evaluate each expression for x = 2. Note that a ^ b means to raise a to the b power. This process is called exponentiation, and the ^ symbol is used on most calculators, and in most computer algebra systems, to represent exponentiation.
......!!!!!!!!...................................
RESPONSE --> I got the first part of the question right, but misread the second part and added 2 and 4 instead of subtracting. I still got the correct answer because 0 divided by any number will equal 0. confidence assessment: 3
.................................................
......!!!!!!!!...................................
09:46:55 2 ^ x + 4 indicates that you are to raise 2 to the x power before adding the 4. 2 ^ (x + 4) indicates that you are to first evaluate x + 4, then raise 2 to this power. If x = 2, then 2 ^ x + 4 = 2 ^ 2 + 4 = 2 * 2 + 4 = 4 + 4 = 8. and 2 ^ (x + 4) = 2 ^ (2 + 4) = 2 ^ 6 = 2*2*2*2*2*2 = 64.
......!!!!!!!!...................................
RESPONSE --> OK self critique assessment: 3
.................................................
......!!!!!!!!...................................
09:57:47 `q003. What is the numerator of the fraction in the expression x - 3 / [ (2x-5)^2 * 3x + 1 ] - 2 + 7x? What is the denominator? What do you get when you evaluate the expression for x = 2?
......!!!!!!!!...................................
RESPONSE --> the numerator of the fraction is x - 3. The denominator is [ ( 2x - 5)^2 * 3x + 1 ] - 2 + 7x x - 3 / [ ( 2x- 5)^2 * 3x + 1] - 2 + 7x 2- 3 / [ ( 2(2) - 5)^2 * 3(2) + 1] - 2 + 7( 2) - 1 / [ ( 4- 5)^2 * 3(2) + 1 ] - 2 + 7 (2) -1/ [ (-1)^2 * 3(2) + 1] - 2 + 7(2) -1/ [ 1* 3(2) + 1] - 2 + 7(2) -1/ ( 3(2) + 1) - 2 + 7(2) -1/ (6 + 1) - 2 + 7(2) -1/ 7 - 2 + 14 -1/ 5 + 14 = -1/ 19 confidence assessment: 3
.................................................
......!!!!!!!!...................................
10:00:18 The numerator is 3. x isn't part of the fraction. / indicates division, which must always precede subtraction. Only the 3 is divided by [ (2x-5)^2 * 3x + 1 ] and only [ (2x-5)^2 * 3x + 1 ] divides 3. If we mean (x - 3) / [ (2x-5)^2 * 3x + 1 ] - 2 + 7x we have to write it that way. The preceding comments show that the denominator is [ (2x-5)^2 * 3x + 1 ] Evaluating the expression for x = 2: - 3 / [ (2 * 2 - 5)^2 * 3(2) + 1 ] - 2 + 7*2 = 2 - 3 / [ (4 - 5)^2 * 6 + 1 ] - 2 + 14 = evaluate in parenthese; do multiplications outside parentheses 2 - 3 / [ (-1)^2 * 6 + 1 ] -2 + 14 = add inside parentheses 2 - 3 / [ 1 * 6 + 1 ] - 2 + 14 = exponentiate in bracketed term; 2 - 3 / 7 - 2 + 14 = evaluate in brackets 13 4/7 or 95/7 or about 13.57 add and subtract in order. The details of the calculation 2 - 3 / 7 - 2 + 14: Since multiplication precedes addition or subtraction the 3/7 must be done first, making 3/7 a fraction. Changing the order of the terms we have 2 - 2 + 14 - 3 / 7 = 14 - 3/7 = 98/7 - 3/7 = 95/7. COMMON STUDENT QUESTION: ok, I dont understand why x isnt part of the fraction? And I dont understand why only the brackets are divided by 3..why not the rest of the equation? INSTRUCTOR RESPONSE: Different situations give us different algebraic expressions; the situation dictates the form of the expression. If the above expression was was written otherwise it would be a completely different expression and most likely give you a different result when you substitute. If we intended the numerator to be x - 3 then the expression would be written (x - 3) / [(2x-5)^2 * 3x + 1 ] - 2 + 7x, with the x - 3 grouped. If we intended the numerator to be the entire expression after the / the expression would be written x - 3 / [(2x-5)^2 * 3x + 1 - 2 + 7x ].
......!!!!!!!!...................................
RESPONSE --> I don't understand why only the brackets divide 3.
.................................................
......!!!!!!!!...................................
10:09:11 `q004. Explain, step by step, how you evaluate the expression (x - 5) ^ 2x-1 + 3 / x-2 for x = 4.
......!!!!!!!!...................................
RESPONSE --> first you do what is in parentheses. ( 4 - 5) which equals -1 then you solve the equation of the exponent. 2(4) -1 which equals 7 then you raise -1 to the 7th power which equals -1 then you divide 3 by 4 which is 3/4 then you would add -1 and 3/4 which is -7/4 then subtract 2 which equals -15/ 4 confidence assessment: 1
.................................................
......!!!!!!!!...................................
10:11:11 We get (4-5)^2 * 4 - 1 + 3 / 1 - 4 = (-1)^2 * 4 - 1 + 3 / 4 - 2 evaluating the term in parentheses = 1 * 4 - 1 + 3 / 4 - 2 exponentiating (2 is the exponent, which is applied to -1 rather than multiplying the 2 by 4 = 4 - 1 + 3/4 - 2 noting that 3/4 is a fraction and adding and subtracting in order we get = 1 3/4 = 7 /4 (Note that we could group the expression as 4 - 1 - 2 + 3/4 = 1 + 3/4 = 1 3/4 = 7/4). COMMON ERROR: (4 - 5) ^ 2*4 - 1 + 3 / 4 - 2 = -1 ^ 2*4 - 1 + 3 / 4-2 = -1 ^ 8 -1 + 3 / 4 - 2. INSTRUCTOR COMMENTS: There are two errors here. In the second step you can't multiply 2 * 4 because you have (-1)^2, which must be done first. Exponentiation precedes multiplication. Also it isn't quite correct to write -1^2*4 at the beginning of the second step. If you were supposed to multiply 2 * 4 the expression would be (-1)^(2 * 4). Note also that the -1 needs to be grouped because the entire expression (-1) is taken to the power. -1^8 would be -1 because you would raise 1 to the power 8 before applying the - sign, which is effectively a multiplication by -1.
......!!!!!!!!...................................
RESPONSE --> I thought that 2x - 1 was the equation of the exponent so therefore I got the problem completely wrong. Now I understand that the number in the parentheses was just being squared. self critique assessment: 2
.................................................
......!!!!!!!!...................................
10:12:02 *&*& Standard mathematics notation is easier to see. On the other hand it's very important to understand order of operations, and students do get used to this way of doing it. You should of course write everything out in standard notation when you work it on paper. It is likely that you will at some point use a computer algebra system, and when you do you will have to enter expressions through a typewriter, so it is well worth the trouble to get used to this notation. Indicate your understanding of the necessity to understand this notation.
......!!!!!!!!...................................
RESPONSE --> I understand that it is necessary to understand this notation. self critique assessment: 3
.................................................
......!!!!!!!!...................................
10:13:53 `q005. At the link http://www.vhcc.edu/dsmith/genInfo/introductory problems/typewriter_notation_examples_with_links.htm (copy this path into the Address box of your Internet browser; alternatively use the path http://vhmthphy.vhcc.edu/ > General Information > Startup and Orientation (either scroll to bottom of page or click on Links to Supplemental Sites) > typewriter notation examples and you will find a page containing a number of additional exercises and/or examples of typewriter notation.Locate this site, click on a few of the links, and describe what you see there.
......!!!!!!!!...................................
RESPONSE --> I see examples of both typewriter notation and standard notation. confidence assessment: 3
.................................................
......!!!!!!!!...................................
10:14:36 You should see a brief set of instructions and over 30 numbered examples. If you click on the word Picture you will see the standard-notation format of the expression. The link entitled Examples and Pictures, located in the initial instructions, shows all the examples and pictures without requiring you to click on the links. There is also a file which includes explanations. The instructions include a note indicating that Liberal Arts Mathematics students don't need a deep understanding of the notation, Mth 173-4 and University Physics students need a very good understanding,
......!!!!!!!!...................................
RESPONSE --> Ok self critique assessment: 3
.................................................
......!!!!!!!!...................................
10:14:50 while students in other courses should understand the notation and should understand the more basic simplifications. There is also a link to a page with pictures only, to provide the opportunity to translated standard notation into typewriter notation.
......!!!!!!!!...................................
RESPONSE --> Ok self critique assessment: 3
.................................................
......!!!!!!!!...................................
10:14:58 end program
......!!!!!!!!...................................
RESPONSE --> Ok self critique assessment: 3
................................................."