course Mth 158 Ia the area of a pool with a raduis of 10 = 100? Ithought it would be 314. I also missed the problem with the sphere. I used the correct formula and a calculator. What did do wrong? P???B??????V????assignment #003003. `query 3
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10:21:06 R.3.12 (was R.3.6) What is the hypotenuse of a right triangle with legs 14 and 48 and how did you get your result?
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RESPONSE --> c^2 = a^2 + b^2 c =50 confidence assessment: 3
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10:21:25 ** The Pythagorean Theorem tells us that c^2 = a^2 + b^2, where a and b are the legs and c the hypotenuse. Substituting 14 and 48 for a and b we get c^2 = 14^2 + 48^2, so that c^2 = 196 + 2304 or c^2 = 2500. This tells us that c = + sqrt(2500) or -sqrt(2500). Since the length of a side can't be negative we conclude that c = +sqrt(2500) = 50. **
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RESPONSE --> ok self critique assessment: 3
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10:23:57 R.3.18 (was R.3.12). Is a triangle with legs of 10, 24 and 26 a right triangle, and how did you arrive at your answer?
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RESPONSE --> 10^2 + 24^2 = 26^2 676 = 673 This is a right triangle. confidence assessment: 3
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10:24:20 ** Using the Pythagorean Theorem we have c^2 = a^2 + b^2, if and only if the triangle is a right triangle. Substituting we get 26^2 = 10^2 + 24^2, or 676 = 100 + 576 so that 676 = 676 This confirms that the Pythagorean Theorem applies and we have a right triangle. **
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RESPONSE --> ok self critique assessment: 3
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10:29:29 R.3.30 (was R.3.24). What are the volume and surface area of a sphere with radius 3 meters, and how did you obtain your result?
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RESPONSE --> V =[4/3[ * pi * 3^3 V = 113.1 m^3 SA = 4 * pi *362 SA = 113.1 m^2 confidence assessment: 3
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10:30:53 ** To find the volume and surface are a sphere we use the given formulas: Volume = 4/3 * pi * r^3 V = 4/3 * pi * 3^3 V = 4/3 * pi * 27 V = 36pi m^3 Surface Area = 4 * pi * r^2 S = 4 * pi * 3^2 S = 4 * pi * 9 S = 36pi m^2. **
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RESPONSE --> My mistake- I did not multiply the values by 4/3. self critique assessment: 2
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10:38:33 R.3.42 (was R.3.36). A pool of radius 10 ft is enclosed by a deck of width 3 feet. What is the area of the deck and how did you obtain this result?
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RESPONSE --> 13^2 * 3.14= 530.66 10^2 * 3.14 = 314 530.66-3.14=216.66 The answer is 216. 66 ft^2 if the deck is circular. confidence assessment: 2
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10:43:29 ** The deck plus the pool gives you a circle of radius 10 ft + 3 ft = 13 ft. The area of the deck plus the pool is therefore pi * (13 ft)^2 = 169 pi ft^2. So the area of the deck must be deck area = area of deck and pool - area of pool = 169 pi ft^2 - 100 pi ft^2 = 69 pi ft^2. **
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RESPONSE --> If the area of a circle is is calculated as pi* r^2, how can it the radius of the pool be 100? It should be 100 * 3.14. self critique assessment: 1
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10:44:22 005. `query 5
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RESPONSE --> self critique assessment: 1
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