phy 121
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Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
f=ma
f=(12kg)3m/s^2
f=36N
#$&*
What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
f=ma
20N= 4kg(a)
5m/s^2= a
#$&*
If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the
object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
f=ma
f=(10kg)(1.5m/s^2)
f=15N
We know that something must be going counter to your force since it is accelerating in the direction of your force at only 15N versus the 20N that you are supplying.
#$&*
What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
Since it is showing the reaction of movement away from you from 15 N of force, we know that something must be going against your force of 20N with at least 5N of force. Other
forces may be involved too just canceling one another out.
#$&*
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Revised: 06 Feb 2010 17:10:16 -0500
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