phy 121
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and
the marble speeds up to 70 cm / sec.
Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
I think that m'dv should be equal before and after so 60g* 80 cm/s + 20g*0 cm/s= 60g*50cm/s + 20g* 70cm/s This is not a true statement so the momentum before and after are not
the same.
#$&*
What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> : The marble would have to be going at the rate of 90 cm/s to give us equivalent momentum.
#$&*
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Revised: 06 Feb 2010 17:16:20 -0500
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10 min.
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4/5 at 10:08 p.m.
&#This looks good. Let me know if you have any questions. &#