cq_1_251

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PHY 201

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** CQ_1_25.1_labelMessages.txt **

A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.

• What are the magnitude and direction of the centripetal acceleration of the ball?

answer/question/discussion: ->->->->->->->->->->->-> :

m=0.110 kg, v=30 cm/s / 100 = 0.30 m/s, r = 0.20 m

a=v^2/r = (0.30 m/s)^2 / 0.20 m = 0.45 m/s^2

This acceleration is directed to the center of the circle.

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• What is the magnitude and direction of the centripetal force required to keep it moving around this circle?

answer/question/discussion: ->->->->->->->->->->->-> :

F_cent = m*a -= 0.110 kg * 0.45 m/s^2 = 0.0495 N

The force is directed towards the center of the circle.

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10 minutes

&#Very good responses. Let me know if you have questions. &#