Phy 201
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 9 seconds
• What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 27. 5 cm/sec
• How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 3.1 cm
• By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 4 seconds
• By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 11.5
• What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 2.875 cm/sec
• What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : 4
• What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : 11.5
• What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : .35
• What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : The graph is increasing
• What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 2.875 cm/sec
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15 minutes
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Solution
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