course Phy 201
The problem:A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion:
V= d / t
V= (8cm/s^2) / (3seconds)
8 cm/s^2 is not a displacement but an acceleration
V= 8/3 cm/s^3
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion:
Average Velocity = (vf+v0) / 2
Average Velocity = (8/3cm/s^3 + 12cm/s) / 2
Average Velocity = 7.3 cm/s^2
• How far will it travel during this interval?
answer/question/discussion:
Displacement = ((vf+v0) / 2) * `dt
Displacement = 7.3 cm/s^2 * 3 seconds
Displacement = 21.9 cm
** I am not sure if I kept the units accurate during this problem. If not, could you please explain to me the correct way to do it. **
"
Note that you should use the form for this specific question to submit it. No problem if, as in this case, I notice the difference, and I often will; however but I'm focused on content and not clerical details so I can't be counted on to do so.
In any case you have misidentified one of these quantities, but your approach is otherwise good.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#