Phy 201
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
For each trial we must find the average velocity.
Average Velocity = 10 meters / 8 sec
Average velocity = 1.25 m/sec
We can now find final velocity
Final velocity = 2.5 m/sec
We can now find acceleration
Acceleration = 2.5 m/sec / 8 sec
Acceleration = .31 m/sec^2
Now for the second trial we do the same:
Average velocity = 10 meters / 5 seconds
Average velocity = 2 m/sec
We can now find final velocity
Final velocity = 4 m/s
We can now find acceleration
Acceleration = 4 m/s / 5 seconds
Acceleration = .8 m/sec^2
Average rate of acceleration = (.8 m/sec^2 - .31m/sec^2) / (8 seconds – 5 seconds)
this should be ave rate of change of accel with respect to ramp slope, not with respect to the time required to roll down the ramp
Average rate of acceleration = .49 m/sec^2 / 3 seconds
Average rate of acceleration = .16 m/sec^3
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15 minutes
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Solution
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