cq_1_021

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PHY 201

Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.

• What is your best guess about the ball's average velocity? 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

I would guess the answer to be 7 cm/sec. What I did is took the average of the two values. 10 cm/sec + 4 cm/sec. 14 cm/sec / 2 = 7 cm/sec

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• Without further information, why is this just a guess?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 The answer 7 cm/sec is only a guess because the problem does not give the amount of time the object need to get from 4 cm/sec to 10 cm/sec.

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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time? 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 Now I would say the average velocity would be 2 cm/sec every second.

math.

10 cm/sec - 4 cm/sec = 6 cm/sec = 'ds

3 sec = 'dt

vAve = 6cm/sec / 3 sec = 2 cm/sec every second.

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6 cm/s is not a displacement. A displacement would be measured in meters.

What term do we use for the quantity we get when we subtract the initial velocity from the final?

And what quantity do we get when we divide that quantity by the change in clock time?

That quantity is not the average velocity. For this question, what is the average velocity, and what therefore is the displacement?

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• At what average rate did its velocity change with respect to clock time during this interval?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 The object changed velocity every second, increasing how fast it went by two units. this we can see from the previous answer.

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You are definitely doing some of the right operations, but you aren't always identifying them correctly.

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