Assignment 5 R4

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course Mth 158

2-3 12:40 pm

005. `* 4

* R.4.36 (was R.5.30). What is the single polynomial that is equal to 8 ( 4 x^3 - 3 x^2 - 1 ) - 6 ( 4 x^3 + 8 x - 2 )?

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Your solution:

8(4x^3 - 3x^2 - 1) -6(4x^3 + 8x - 2)

Multiply 8 by the first polynomial, then -6 by its corresponding polynomial

32x^3 - 24x^2 - 8 - 24x^3 - 48x + 12

Add/subtract like terms

8x^3 - 24x^2 - 48x + 4

confidence rating #$&*: 3

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Given Solution:

* * ** ERRONEOUS STUDENT SOLUTION: To make this problem into a single polynomial, you can group like terms together. (8-6)+ (4x^3-4x^3) + (-3x^2) + (8x) + (-1+2).

Then solve from what you just grouped...2 (-3x^2+8x+1).

INSTRUCTOR CORRECTION:

8 is multiplied by the first polynomial and 6 by the second. You need to follow the order of operations.

Starting with

8 ( 4 x^3 - 3 x^2 - 1 ) - 6 ( 4 x^3 + 8 x - 2 ) use the Distributive Law to get

32 x^3 - 24 x^2 - 8 - 24 x^3 - 48 x + 12. Then add like terms to get

8x^3 - 24x^2 - 48x + 4 **

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Self-critique (if necessary):ok

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Self-critique Rating:3

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Question:

* R.4.60 (was R.5.54). What is the product (-2x - 3) ( 3 - x)?

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Your solution:

(-2x - 3)(3 - x)

Use the distributive property

-6x + 2x^2 - 9 + 3x

Combine like terms

2x^2 - 3x - 9

confidence rating #$&*:3

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Given Solution:

* * ** Many students like to use FOIL but it's much better to use the Distributive Law, which will later be applied to longer and more complicated expressions where FOIL does not help a bit.

Starting with

(-2x - 3) ( 3 - x) apply the Distributive Law to get

-2x ( 3 - x) - 3 ( 3 - x). Then apply the Distributive Law again to get

-2x(3) - 2x(-x) - 3 * 3 - 3 ( -x) and simiplify to get

-6x + 2 x^2 - 9 + 3x. Add like terms to get

2 x^2 - 3 x - 9. **

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Self-critique (if necessary):ok

I have never been comfortable with the FOIL method. I have no issues with just distributing the terms.

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Self-critique Rating:3

@&

FOIL is useful for factoring certain trinomials. Otherwise I consider it useless and worse than useless, since it distracts from the distributive law.

*@

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Question:

* R.4.66 (was R.5.60). What is the product (x - 1) ( x + 1) and how did you obtain your result using a special product formula?

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Your solution:

(x - 1)(x + 1)

The product is (x^2 - 1)

I used the difference of two squares formula- (x^2 - a^2)

confidence rating #$&*:3

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Given Solution:

Starting with

(x-1)(x+1) use the Distributive Law once to get

x ( x + 1) - 1 ( x+1) then use the Distributive Law again to get

x*x + x * 1 - 1 * x - 1 * 1. Simplify to get

x^2 +- x - x + - 1. Add like terms to get

x^2 - 1. **

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Self-critique (if necessary):ok

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Self-critique Rating:3

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Question:

* R.4.84 (was R.5.78). What is (2x + 3y)^2 and how did you obtain your result using a special product formula?

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Your solution:

(2x + 3y)^2

MathXL pushes for the use of the perfect square formula, but even after doing so I still go back and check the work by distributing.

(2x + 3y)^2=4x^2 + 12xy + 9x^2

Or

(2x + 3y)(2x + 3y)

Distribute

4x^2 + 6xy + 6xy + 9y^2

Combine like terms

4x^2 + 12xy + 9y^2

I prefer the latter method; I’m just more comfortable with it even though it requires a tad more work.

confidence rating #$&*:3

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Given Solution:

* * ** The Special Product is

• (a + b)^2 = a^2 + 2 a b + b^2.

Letting a = 2x and b = 3y we substitute into the right-hand side a^2 + 2 a b + b^2 to get

(2x)^2 + 2 * (2x) * (3y) + (3y)^2, which we expand to get

4 x^2 + 12 x y + 9 y^2. **

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Self-critique (if necessary):ok

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Self-critique Rating:3

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Question:

* R.4.105 \ 90 (was R.5.102). Explain why the degree of the product of two polynomials equals the sum of their degrees.

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Your solution:

The distributive property insists that the degree (highest exponent) of each polynomial be multiplied, which, according to the law of exponents means that rather than multiplying the two exponents you will add them.

confidence rating #$&*: 3

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Given Solution:

* * ** STUDENT ANSWER AND INSTRUCTOR COMMENTS: The degree of the product of two polynomials equals the sum of their degrees because you use the law of exponenents and the ditributive property.

INSTRUCOTR COMMENTS: Not bad.

A more detailed explanation:

The Distributive Law ensures that you will be multiplying the highest-power term in the first polynomial by the highest-power term in the second.

Since the degree of each polynomial is the highest power present, and since the product of two powers gives you an exponent equal to the sum of those powers, the highest power in the product will be the sum of the degrees of the two polynomials.

Since the highest power present in the product is the degree of the product, the degree of the product is the sum of the degrees of the polynomials. **

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Self-critique (if necessary):ok

I have never been very good at explaining these things in a fluent manner. At least I don’t think I have been. I can understand the concept completely, and have no problem showing someone else how to do the problems, but when it comes to writing down an explanation that isn’t just a bunch of sentence fragments thrown here and there I fall short.

@&

You had a good statement in your answer.

*@

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Self-critique Rating:3

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Question:

* R.4.105 \ 90 (was R.5.102). Explain why the degree of the product of two polynomials equals the sum of their degrees.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

The distributive property insists that the degree (highest exponent) of each polynomial be multiplied, which, according to the law of exponents means that rather than multiplying the two exponents you will add them.

confidence rating #$&*: 3

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

* * ** STUDENT ANSWER AND INSTRUCTOR COMMENTS: The degree of the product of two polynomials equals the sum of their degrees because you use the law of exponenents and the ditributive property.

INSTRUCOTR COMMENTS: Not bad.

A more detailed explanation:

The Distributive Law ensures that you will be multiplying the highest-power term in the first polynomial by the highest-power term in the second.

Since the degree of each polynomial is the highest power present, and since the product of two powers gives you an exponent equal to the sum of those powers, the highest power in the product will be the sum of the degrees of the two polynomials.

Since the highest power present in the product is the degree of the product, the degree of the product is the sum of the degrees of the polynomials. **

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Self-critique (if necessary):ok

I have never been very good at explaining these things in a fluent manner. At least I don’t think I have been. I can understand the concept completely, and have no problem showing someone else how to do the problems, but when it comes to writing down an explanation that isn’t just a bunch of sentence fragments thrown here and there I fall short.

@&

You had a good statement in your answer.

*@

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Self-critique Rating:3

#*&!

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Question:

* R.4.105 \ 90 (was R.5.102). Explain why the degree of the product of two polynomials equals the sum of their degrees.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

The distributive property insists that the degree (highest exponent) of each polynomial be multiplied, which, according to the law of exponents means that rather than multiplying the two exponents you will add them.

confidence rating #$&*: 3

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

* * ** STUDENT ANSWER AND INSTRUCTOR COMMENTS: The degree of the product of two polynomials equals the sum of their degrees because you use the law of exponenents and the ditributive property.

INSTRUCOTR COMMENTS: Not bad.

A more detailed explanation:

The Distributive Law ensures that you will be multiplying the highest-power term in the first polynomial by the highest-power term in the second.

Since the degree of each polynomial is the highest power present, and since the product of two powers gives you an exponent equal to the sum of those powers, the highest power in the product will be the sum of the degrees of the two polynomials.

Since the highest power present in the product is the degree of the product, the degree of the product is the sum of the degrees of the polynomials. **

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Self-critique (if necessary):ok

I have never been very good at explaining these things in a fluent manner. At least I don’t think I have been. I can understand the concept completely, and have no problem showing someone else how to do the problems, but when it comes to writing down an explanation that isn’t just a bunch of sentence fragments thrown here and there I fall short.

@&

You had a good statement in your answer.

*@

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Self-critique Rating:3

#*&!#*&!

&#Your work looks very good. Let me know if you have any questions. &#