#$&*
Phys201
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_03.1_labelMessages.txt **
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
• What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
vAve=`ds/`dt
vAve=30 cm/5sec
vAve=6 cm/sec
Use avg velocity equation. Plug in numbers. Note that this is uniform acceleration.
#$&*
• If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
If the acceleration is uniform and the initial velocity is 0. I believe that the final velocity is 0 because the ball would come to a complete stop.
#$&*
• By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The velocity does not change because in the problem it states that uniform acceleration is taking place. Thus, the velocity stays the same the entire time.
#$&*
@&
Acceleration is the rate at which velocity changes.
Unless acceleration happens to be zero, the velocity must change.
Starting with velocity 0, the ball wouldn't travel 30 cm without changing velocity.
*@
• At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Ave/`ds=`dt would be used.
6cm/sec/5 sec= 1 cm/sec
Not quite sure if I did this correctly. I believe I used the correct equation but not sure if I used the correct numbers.
#$&*
@&
6 / 5 is not 1.
cm/sec / sec is not cm/sec.
*@
• What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
In this instance, I believe it would be a straight horizontal line going at a constant rate. I think the initial and final velocities are zero. We know it is uniform acceleration, so the velocity remains constant. Thus, a constant straight line would be created.
#$&*
@&
The line would only be horizontal if acceleration was zero, which is not the case.
*@
*#&!
@&
&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes. &#
*@