Phy 201
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A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
• What will be the velocity of the ball after one second?
answer/question/discussion: ->->->->->->->->->->->-> : 25+10*1=35m/sec
• What will be its velocity at the end of two seconds?
answer/question/discussion: ->->->->->->->->->->->-> : 25+10*2=45m/sec
• During the first two seconds, what therefore is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> :45+25/2=35m/sec
• How far does it therefore rise in the first two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :35*2=70m
• What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: ->->->->->->->->->->->-> :25+10*3=55m/sec
25+40=65m/sec
• At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: ->->->->->->->->->->->-> : not sure
• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: ->->->->->->->->->->->-> :25+65/2=45m/sec
• How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> : ds=85+25/2 *6=55/2=27.5m
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10 minutes
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&#Please compare your solutions with the expanded discussion at the link
Solution
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