Phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> : Force on 5kg mass system= 5*9.8=49N
Force on 6kg mass system= 6*9.8=58.8N
Net force=58.8-49=9.8
Acceleration=Fnet/mass=9.8/11=.89m/sec^2
Direction will be towards the 6kg mass downwards.
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> : I think the direction of motion would be negative, but not sure how to calculate the magnitude of speed.
Just a guess work here, Force on 5kg mass=5*9.8=49N
Acceleration=49/5=9.8
a=x-1.8/1=9.8
x=9.8+1.8=11.6m/sec
You already figured out the acceleration of the system.
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> : I am not very sure, but I think they are in the same direction and the system speeds up
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10mins
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Good start. See my note, and the link below, for more:
&#Please compare your solutions with the expanded discussion at the link
Solution
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