Phy 201
A displacement vector from one point to another is a vector of the
form<x displacement, y displacement>
The vector represents how you would move (more or less, how far you
would have to go in each direction) to get from one point to another.The magnitude of the displacement vector is
magnitude = sqrt( (x displacement)^2 + (y displacement)^2 )
and the angle of the vector with the positive x direction is
angle = arcTan ( (y displacement) / (x displacement) ), plus 180
deg if the x displacement is negative.
What is the horizontal displacement from the first point to the
second?What is the vertical displacement from the first point to the
second?What therefore is the vector from the first point to the second?
(You can either give the vector in the form <x displacement, y displacement> or you can give its magnitude and angle; the two forms are equivalent. The first form is the simpler form, and this form will probably be your choice). What is the magnitude of this vector? answer/question/discussion: ->->->->->->->->->->->-> scussion: * What vector do you get when you divide this vector by its magnitude? (Specify the x and y components of the resulting vector). answer/question/discussion: ->->->->->->->->->->->-> scussion: * What vector do you get when you multiply this new vector by the tension? answer/question/discussion: ->->->->->->->->->->->-> scussion: * What are the x and y coordinates of the new vector? answer/question/discussion: ->->->->->->->->->->->-> scussion:** **
10 mns** **
I am sorry but my brain is not going in any direction for these question. Do we have to use the x sine theta and y sine theta formula.See my notes, which should help you get started. Also note the Introductory Problem Set 5 questions assigned previously, I believe in Asst 14.