Phy 231
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
v0=0m/s
‘ds=2m
`dt=.64s
vAve= 2/.64= 3.1m/s
vf= 2*3.1= 6.25
`dv/`dt=aAve, so (6.25m/s) /.64s= 9.7m/s^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
`ds/`dt= 5m/1.05s= 4.76m/s= vAve and 4.76m/s=(v0+vf)/2= 2(4.76)= 9.52m/s
aAve=`dv/`dt= 9.52m/s/1.05s= 9.14m/s^2; the values are very close.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
The acceleration of the two products are not exactly the same, they differ 7% which means that they are not totally consistents, but very close to the same vale.
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10 minutes
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