cq_1_081

Phy 231

Your 'cq_1_08.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.

• What will be the velocity of the ball after one second?

answer/question/discussion: ->->->->->->->->->->->-> :

v0=25m/s

a= 10m/s^2

`dt=1s

Vf=25+(-10)(1)= 15m/s

So vf= 15m/s

#$&*

• What will be its velocity at the end of two seconds?

answer/question/discussion: ->->->->->->->->->->->-> :

`dt= 2s and

Vf=25+(-10)(2)= 5m/s

#$&*

• During the first two seconds, what therefore is its average velocity?

answer/question/discussion: ->->->->->->->->->->->-> :

25+5= 30/2= 15m/s

#$&*

• How far does it therefore rise in the first two seconds?

answer/question/discussion: ->->->->->->->->->->->-> : 15m/s*2= 30m

#$&*

• What will be its velocity at the end of an additional second, and at the end of one more additional second?

answer/question/discussion: ->->->->->->->->->->->-> :

vf= 25+(-10)(3)= -5m/s

vf=25+(-10)(4)= -15m/s

#$&*

• At what instant does the ball reach its maximum height, and how high has it risen by that instant?

answer/question/discussion: ->->->->->->->->->->->-> :

at 2.5 seconds the velocity should reach zero, 0m/s

#$&*

• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?

answer/question/discussion: ->->->->->->->->->->->-> : vAve= -15+25/2= 5m/s

5m/s*4s= 20m

#$&*

• How high will it be at the end of the sixth second?

answer/question/discussion: ->->->->->->->->->->->-> :

0m

#$&*

** **

20 minutes

** **

&#Very good work. Let me know if you have questions. &#

cq_1_081

Phy 231

Your 'cq_1_08.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.

• What will be the velocity of the ball after one second?

answer/question/discussion: ->->->->->->->->->->->-> :

v0=25m/s

a= 10m/s^2

`dt=1s

Vf=25+(-10)(1)= 15m/s

So vf= 15m/s

#$&*

• What will be its velocity at the end of two seconds?

answer/question/discussion: ->->->->->->->->->->->-> :

`dt= 2s and

Vf=25+(-10)(2)= 5m/s

#$&*

• During the first two seconds, what therefore is its average velocity?

answer/question/discussion: ->->->->->->->->->->->-> :

25+5= 30/2= 15m/s

#$&*

• How far does it therefore rise in the first two seconds?

answer/question/discussion: ->->->->->->->->->->->-> : 15m/s*2= 30m

#$&*

• What will be its velocity at the end of an additional second, and at the end of one more additional second?

answer/question/discussion: ->->->->->->->->->->->-> :

vf= 25+(-10)(3)= -5m/s

vf=25+(-10)(4)= -15m/s

#$&*

• At what instant does the ball reach its maximum height, and how high has it risen by that instant?

answer/question/discussion: ->->->->->->->->->->->-> :

at 2.5 seconds the velocity should reach zero, 0m/s

#$&*

• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?

answer/question/discussion: ->->->->->->->->->->->-> : vAve= -15+25/2= 5m/s

5m/s*4s= 20m

#$&*

• How high will it be at the end of the sixth second?

answer/question/discussion: ->->->->->->->->->->->-> :

0m

#$&*

** **

20 minutes

** **

&#Very good work. Let me know if you have questions. &#

&#Please compare your solutions with the expanded discussion at the link

Solution

Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#