cq_1_151

Phy 201

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A rubber band begins exerting a tension force when its length is 8 cm. As it is stretched to a length of 10 cm its tension increases with length, more or less steadily, until at the 10 cm length the tension is 3 Newtons.

• Between the 8 cm and 10 cm length, what are the minimum and maximum tensions?

answer/question/discussion: ->->->->->->->->->->->-> : We know the minimum is at 8 cm at 0newtons and the max is at 10cm at 3 newtons

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• Assuming that the tension in the rubber band is 100% conservative (which is not actually the case) what is its elastic potential energy at the 10 cm length?

answer/question/discussion: ->->->->->->->->->->->-> : we know that the `ds= 2cm b/c 10cm-8cm= 2cm

and the `dwnet= 3N so 2cm*3N= 6 joules (im not sure If I need to do this calculation in m or cm?????????) if in m then .06 joules

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• If all this potential energy is transferred to the kinetic energy of an initially stationary 20 gram domino, what will be the velocity of the domino?

answer/question/discussion: ->->->->->->->->->->->-> : We can use the equation for KE which is 0.06=.5(.02)(v^2)=v= 2.45m/s

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• If instead the rubber band is used to 'shoot' the domino straight upward, then how high will it rise?

answer/question/discussion: ->->->->->->->->->->->-> : we can use the vf^2 equation= v0+2a`ds we find that 0=(2.45m/s)^2+2(-9.8m/s)`ds= -13.6m/s^2 so 6.0025m^2/s^2/-13.6= 0.44m

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20 minutes

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