phy 201
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For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.
• A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> :
Yes you can directly determine the vAve. Yes you can directly determin ‘dv. Both of the velocities are given.
20-10= 10cm/s=’dv
20+10= 30/2= 15cm/s= vAve
15cm/s= 45cm/’dt= 3seconds
Acceleration= 10cm/s/3= 3.33cm/s^2
V0= 10cm/s
Vf= 20cm/s
‘ds= 45cm
‘dt= 3 seconds
A=3.33cm/s^2
• A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> :
No, you have a few steps before determining vAve. No you cannot directly determine ‘dv.
v0=30cm/s
vf=50cm/s
‘dt=3s
‘ds=120cm
A= 10cm/s^2
10cm/s^2=’dv/3seconds= 30m/s
vAve= 30+50=80/2= 40cm/s
= 40cm/s= ds/3seconds= 120cm
• A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> :
No, you cannot directly determine vAve. No you cannot directly determine ‘dv. There are several steps involved before determining that value
v0= 0cm/s
vf= 34.7cm/s
‘dt= 1.73
‘ds= 30cm
Acceleration- 20cm/s^2
`ds = v0 `dt + .5 a `dt^2
30cm= 0cm/s(dt)+.5(20cm/s^2)(‘dt^2)
30cm=10cm/s^2(‘dt^2)= 1.73 seconds
vAve= 30/1.73= 17.3cm/s
=17.3x2= 34.7cm/s= vf
Then for each situation answer the following:
• Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> :
• Is it possible to directly determine `dv?
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20minutes
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&#Your work looks very good. Let me know if you have any questions. &#