PHY 231
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Copy the problem below into a text editor or word processor.
• This form accepts only text so a text editor such as Notepad is fine.
• You might prefer for your own reasons to use a word processor (for example the formatting features might help you organize your answer and explanations), but note that formatting will be lost when you submit your work through the form.
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• As you will see within the first few assignments, there is an easily-learned keyboard-based shorthand that doesn't look quite as pretty as word-processor symbols, but which gets the job done much more efficiently.
You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.
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The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I sketched the v vs. t graph, with time as the independent variable and v as the dependent variable. Time, in seconds, is along the x-axis and the velocity, expressed as cm-s^-1, is plotted along the y-axis.
#$&*
• Sketch a straight line segment between these points.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I drew a straight line between the points, ( 4, 10 ) and ( 9, 40 ).
#$&*
• What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The rise is 30, or 30 cm/s. The slope is 6, or 6 cm/sec.^2. And the run is 5, or 5 seconds.
*All Calculations Shown Below*
Rise :
Rise = Y2 - Y1
= 40 cm/s - 10 cm/s
= 30 cm/s
Slope:
Slope = ( Y2 - Y1 ) / ( X2 - X1 )
= ( 40 cm/s - 10 cm/s ) / ( 9 sec. - 4 sec. )
= ( 30 cm/s ) / ( 5 sec. )
= 6 cm / sec.^2
Run:
Run = ( X2 - X1 )
= ( 9 sec. - 4 sec. )
= 5 sec.
#$&*
• What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The area beneath the segment from ( 4, 10 ) and ( 9, 40 ) is 125 cm squared.
Calculations:
( 4, 10 ) to ( 9, 10 )
9 - 4 = 5
Area of Rectangle:
5 s * 10 cm/ s = 50 cm
(4, 10 ) and ( 9, 10 ) to ( 9, 40 )
50 cm +... ( From above calculation...)
40 cm/s - 10 cm/s = 30 cm/s
Area of Triangle:
( 5 s * 30 cm/s ) / 2
( 150 cm ) / 2
= 75 cm
50 + 75 cm = 125 cm
#$&*
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Copy and paste your work into the box below and submit as indicated:
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15 minutes
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This looks very good. Let me know if you have any questions.