cq_1_051

PHY 231

Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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Copy the problem below into a text editor or word processor.

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• As you will see within the first few assignments, there is an easily-learned keyboard-based shorthand that doesn't look quite as pretty as word-processor symbols, but which gets the job done much more efficiently.

You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.

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The problem:

A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

• What will be its velocity after the 3 seconds has elapsed?

answer/question/discussion: ->->->->->->->->->->->-> :

Work Shown:

- Remember that velocity is expressed as cm/ s

- On a time interval at, 0 seconds, the ball is already traveling at 12 cm/ s

- The rate the velocity changed is at 8 cm/ s^2

Change in Velocity = ( 8 cm/ s^2 )* ( 3 s ) = 24 cm/ s

'dv = 24 cm/s

24 cm/ s + 12 cm/ s = 36 cm/ s

After 3 seconds, the ball's velocity is 36 cm/s.

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• Assuming that acceleration is constant, what will be its average velocity during this interval?

answer/question/discussion: ->->->->->->->->->->->-> :

It's average velocity would therefore be 24 cm/ s.

Calculation:

(( Final + Initial ) / 2 ) = Average Velocity ( Ave. Vel. )

(( 36 cm/ s + 12 cm/s ) / 2) = Ave. Vel.

(( 48 cm/ s ) / 2 ) = Ave. Vel.

( 24 cm/ s ) = Ave. Vel.

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• How far will it travel during this interval?

answer/question/discussion: ->->->->->->->->->->->-> :

During this three second interval, the ball would travel 72 cm.

Calculations:

Ave. Vel. * Time Interval = Distance

24 cm/ s * 3 s = 72 cm

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Copy and paste your work into the box below and submit as indicated:

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15 minutes

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&#Very good work. Let me know if you have questions. &#