PHY 231
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The total force on the 2-mass, frictionless system will be 107.8 N ( 11 kg * 9.8 m/s^2 ). The net force is 9.8 (( 6 * 9.8) - (5 * 9.8 ))N. The magnitude of the acceleration is .89 m/s^2 ( 9.8 N / 11 kg ) and its direction is positive (assuming opposing forces ), in which the extra 1 kg in 6 kg descends.
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
The speed will be about .91 meters per second ( 1.8 m/s -.89 m/s/s ). And its direction, as compared with the last one, will be in the negative direction ( downwards ) still.
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
During the first second, the velocity and acceleration are in opposite directions. The velocity is negative, going in the downwards direction. And the acceleration is going in the positive direction, causing the system to slow down, moving ultimately towards an equilibrium point.
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20 Minutes
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Very good. The link below is just for your reference.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#