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PHY 201
Your 'cq_1_01.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_01.1_labelMessages **
The problem:
Here is the definition of rate of change of one quantity with respect to another:
The average rate of change of A with respect to B on an interval is
• average rate of change of A with respect to B = (change in A) / (change in B)
Apply the above definition of average rate of change of A with respect to B to each of the following. Be sure to identify the quantity A, the quantity B and the requested average rate.
• If the position of a ball rolling along a track changes from 10 cm to 20 cm while the clock time changes from 4 seconds to 9 seconds, what is the average rate of change of its position with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average rate of change would be (20 – 10 cm) / (9 – 4 s) = 10 cm / 5 s = 2 cm /s.
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• If the velocity of a ball rolling along a track changes from 10 cm / second to 40 cm / second during an interval during which the clock time changes by 3 seconds, then what is the average rate of change of its velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
(40 - 10 cm/s) / 3 s = 30 cm/s / 3 s = 10 cm/s^2 I am not 100% sure on this, wouldn’t the seconds cancel out and you just get a distance of 10 cm? The squared seconds would represent acceleration, would it not?
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cm / s^2 is indeed a unit of acceleration.
A preview:
average acceleration is the average rate of change of velocity with respect to clock time.
So what you have calculated here is indeed an average acceleration.
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• If the average rate at which position changes with respect to clock time is 5 cm / second, and if the clock time changes by 10 seconds, by how much does the position change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
5 cm / s = Distance / 10 seconds = (10 s)(5 cm /s) = Distance = 50 cm. The object would have changed by 50 cm in that 10 second timeframe.
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• You will be expected hereafter to know and apply, in a variety of contexts, the definition given in this question. You need to know this definition word