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PHY 201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.1_labelMessages **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
`ds = v0 `dt + .5 a `dt^2 => a = ('ds / (0.5 * 'dt^2) - v0'dt
'ds = 2 m, 'dt = 0.64 s, v0 = 0 m/s
a = (2 m / (0.5 * (0.64 s)^2) - (0 m/s * 0.64 s)
a = 9.77 m/s^2 which is rounded to 9.8 m/s^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->->
a = ('ds / (0.5 * 'dt^2) - v0'dt
a = 5 m / (0.5 * (1.05 s)^2 - (0 m/s * 1.05 s) = 9.1 m/s^2
No, it is not very consistent with the first problem. The acceleration does not match, and it does not match the acceleration of gravity.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
The first one is, however, the second one is slightly off.
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7 mins
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&#Very good responses. Let me know if you have questions. &#