cq_1_091

#$&*

PHY 201

Your 'cq_1_09.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_09.1_labelMessages **

A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds. 

• What are its average velocity, final velocity and acceleration? 

answer/question/discussion: ->->->->->->->->->->->-> :

 'ds = 20 cm, v0 = 0 m/s, 'dt = 2 s

vAve = 'ds / 'dt = 20 cm / 2 s =10 cm/s

vAve = (vf + v0) / 2

vf = 2(vAve) - v0 = 2(10 cm/s) - 0 m/s = 20 cm/s

vf = v0 + a'dtt => (vf - v0) / t = a

a = (vf) / 'dt = 20 cm/s / 2 s = 10 cm/s^2

#$&*

• If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration? 

answer/question/discussion: ->->->->->->->->->->->-> :

 'dt = 2 s / 1.03 = 1.94 s

vAve = 'ds / 'dt = 20 cm / 1.94 s = 10.3 cm/s

vf = 2(vAve) - v0 = 2(10.3 cm/s) = 20.6 cm/s

a = vf / 'dt = 20.6 cm/s / 1.94 s = 10.6 cm/s^2

#$&*

• What is the percent error in each? 

answer/question/discussion: ->->->->->->->->->->->-> :

vf percent error = (1 - (20.0 / 20.6)) * 100 = 2.91%

a percent error = (1 - (10 / 10.6)) * 100 = 5.66%

#$&*

• If the percent error is the same for both velocity and acceleration, explain why this must be so. 

answer/question/discussion: ->->->->->->->->->->->-> :

They are not the same.

#$&*

• If the percent errors are different explain why it must be so.

answer/question/discussion: ->->->->->->->->->->->-> :

I am not 100% sure on how to explain this. But the smaller the number, for example 10 and 10.6, the percent error is higher, however, as the numbers become larger the percent difference is smaller.

I am hoping you will explain this in better mathematical way.

@&

The uncertainty in the time interval gives you an approximate 3% error in the final velocity. You use the time interval, which has a 3% error, along with the final velocity, which now has a 3% error, to calculate the acceleration. The two 3% errors compound, giving you a 6% error.

More rigorous mathematical arguments are possible, but this is sufficient for the present.

*@

#$&*

** **

10 mins

** **

self-critique #$&*

#$&* self-critique

self-critique rating

rating #$&*:

&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.

Then please compare your old and new solutions with the expanded discussion at the link

Solution

Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.

If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#

&#Good responses. See my notes and let me know if you have questions. &#

t difficult to revise your results, most of which follow a valid reasoning process.

&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).

Be sure to include the entire document, including my notes.

&#

*@