cq_1_111

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PHY 201

Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_11.1_labelMessages **

Answer the following based on Newton's Second Law:

• How much net force is required to accelerate a 12 kg mass at 3 m/s^2? 

answer/question/discussion: ->->->->->->->->->->->-> :

f_net = m * a = 12 kg * 3 m/s^2 = 36 kg * m/s^2 = 36 N

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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons? 

answer/question/discussion: ->->->->->->->->->->->-> :

 f_net = m * a => a = f_net / m = 20 kg*m/s^2 / 4 kg = 5 m/s^2

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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own? 

answer/question/discussion: ->->->->->->->->->->->-> :

 20 kg*m/s^2 / 10 kg = 2 m/s^2.

Because I am only getting 1.5 m/s^2 and not 2 m/s^2, then there must be something opposing my force.

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• What is the total of all those forces and in what direction does this total act?

answer/question/discussion: ->->->->->->->->->->->-> :

 10 kg * 1.5 m/s^2 = 15 N. I have a frictional force of -5 N acting against my force of 20 N

f_net = F + Ffrict = 20 N + (-5 N) = 15 N

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10 mins

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