#$&* PHY 201
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When flat, the rhythm gets slower and slower. When tilted slightly, the rhythm speeds up slightly then stops. #$&*  If the bracket is tilted forward a bit, as shown in the figure below, the pearl will naturally hang away from the bracket. Tilt the bracket forward a little bit (not as much as shown in the figure, but enough that the pearl definitely hangs away from the bracket). Keep the bracket stationary and release the pendulum. Note whether the pearl strikes the bracket more and more frequently or less and less frequently with each bounce. Again listen to the rhythm of the sounds made by the ball striking the bracket. • Do the sounds get closer together or further apart, or does the rhythm remain steady? I.e., does the rhythm get faster or slower, or does it remain constant? • Repeat a few times if necessary until you are sure of your answer. Insert your answer into the box below, and give a good description of what you heard.your response &&&&&&&&&&&&&&&&&&
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The rhythm gets slower. #$&*  If the bracket is placed on a perfectly level surface, the pearl will hang straight down, just barely touching the bracket. However most surfaces on which you might place the bracket aren't perfectly level. Place the bracket on a smooth surface and if necessary tilt it a bit by placing a shim (for a shim you could for example use a thin coin, though on most surfaces you wouldn't need anything this thick; for a thinner shim you could use a tightly folded piece of paper) beneath one end or the other, adjusting the position and/or the thickness of the shim until the hanging pearl just barely touches the bracket. Pull the pearl back then release it. If the rhythm of the pearl bouncing off the bracket speeds up or slows down, adjust the level of the bracket, either tilting it a bit forward or a bit backward, until the rhythm becomes steady.  Describe the process you used to make the rhythm steady, and describe just how steady the rhythm was, and how many times the pendulum hit the bracket..your response &&&&&&&&&&&&&&&&&&
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I put a small washer at the rear of the stand, and the pendulum appeared to be steady after a few test. #$&* On a reasonably level surface, place one domino under each of the top left and right corners of your closed textbook, with the front cover upward. Place the bracket pendulum on the middle of the book, with the base of the bracket parallel to one of the sides of the book. Release the pendulum and observe whether the sounds get further apart or closer together. Note the orientation of the bracket and whether the sounds get further apart or closer together. Now rotate the base of the bracket 45 degrees counterclockwise and repeat, being sure to note the orientation of the bracket and the progression of the sounds. Rotate another 45 degrees and repeat. Continue until you have rotated the bracket back to its original position. Report your results in such a way that another student could read them and duplicate your experiment exactly. Try to report neither more nor less information than necessary to accomplish this goal. Use a new line to report the results of each new rotation.your response &&&&&&&&&&&&&&&&&&
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Pendulum position, progression of sound 270 deg, slower 225 deg, steady 180 deg, faster 135 deg, slower 90 deg, slower 45 deg, faster 0 deg, steady 315 deg, steady then slower #$&* Describe how you would orient the bracket to obtain the most regular 'beat' of the pendulum.your response &&&&&&&&&&&&&&&&&&
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Apparently, oriented at 315 deg, 0 deg, or 225 deg showed signs of the most regular beat. I will chose 315 again. #$&* Orient the bracket in this position and start the TIMER program. Adjust the pendulum to the maximum length at which it will still bounce regularly. Practice the following procedure for a few minutes: Pull the pendulum back, ready to release it, and place your finger on the button of your mouse. Have the mouse cursor over the Click to Time Event button. Concentrate on releasing the pendulum at the same instant you click the mouse, and release both. Do this until you are sure you are consistently releasing the pendulum and clicking the mouse at the same time. Now you will repeat the same procedure, but you will time both the instant of release and the instant at which the pendulum 'hits' the bracket the second time. The order of events will be: • click and release the pendulum simultaneously • the pendulum will strike the bracket but you won't click • the pendulum will strike the bracket a second time and you will click at the same instant We don't attempt to time the first 'hit', which occurs too soon after release for most people to time it accurately. Practice until you can release the pendulum with one mouse click, then click again at the same instant as the second strike of the pendulum. When you think you can conduct an accurate timing, initialize the timer and do it for real. Do a series of 8 trials, and record the 8 time intervals below, one interval to each line. You may round the time intervals to the nearest .001 second. Starting in the 9th line, briefly describe what your numbers mean and how they were obtained.your response &&&&&&&&&&&&&&&&&&
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Test, time interval 1, 0.53 2, 0.5339 3, 0.488 4, 0.466 6, 0.489 7, 0.474 8, 0.447 The numbers were obtained by taking the time interval between the initial release of the pendulum and the second strike of the pendulum against the frame with the pendulum positioned at 315 degrees on the textbook with one domino under each top corner of the book. #$&* Finally, you will repeat once more, but you will time every second 'hit' until the pendulum stops swinging. That is, you will release, time the second 'hit', then time the fourth, the sixth, etc.. Practice until you think you are timing the events accurately, then do four trials. Report your time intervals for each trial on a separate line, with commas between the intervals. For example look at the format shown below: .925, .887, .938, .911 .925, .879, .941 etc. In the example just given, the second trial only observed 3 intervals, while the first observed 4. This is possible. Just report what happens in the space below. Then on a new line give a brief description of what your results mean and how they were obtained.your response &&&&&&&&&&&&&&&&&&
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0.617, 0.767, 0.722 0.522, 0.754, 0.78 0.544, 0.747, 0.837, 1.212 It shows that the pendulum is obviously slowing down as the number of hits occur.your response &&&&&&&&&&&&&&&&&&
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13.6 cm #$&* If you have timed these events accurately, you will see clearly that the time from release to the second 'hit' appears to be different than the time between the second 'hit' and the fourth 'hit'. On the average, • how much time elapses between release and the second 'hit' of the pendulum, • how much time elapses between the second and fourth 'hit' and • how much time elapses between the fourth and sixth 'hit'? Report your results as three numbers separated by commas, e.g., .63, .97, .94your response &&&&&&&&&&&&&&&&&&
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0.561, 0.756, 0.7797 #$&* A full cycle of a free pendulum is from extreme point to equilibrium to opposite extreme point then back to equilibrium and finally back to the original extreme point (or almost to the original extreme point, since the pendulum is losing energy as it swings).. The pearl pendulum is released from an 'extreme point' and strikes the bracket at its equilibrium point, so it doesn't get to the opposite extreme point. If an interval consists of motion from extreme point to equilibrium, or from equilibrium to extreme point, how many intervals occur between release and the first 'hit'?your response &&&&&&&&&&&&&&&&&&
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Wouldn't' it be a quarter of an interval. For a full-cycle, the pendulum goes from extreme point to equilibrium, which is a quarter of a cycle, from equilibrium to opposite extreme point which is half a cycle, from opposite extreme point back to equilibrium would be 3/4 of a cycle, and from equilibrium back to beginning extreme point would be 1 full cycle. But thinking about it in terms of this pendulum, from extreme point to equilibrium would be half a cycle, and then from equilibrium to extreme point one cycle. #$&*your response &&&&&&&&&&&&&&&&&&
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It would be a full cycle between the first hit and the second hit based on my description above. Its going from equilibrium to extreme point, half a cycle, and then from extreme point back to equilibrium which is another half cycle to equal 1 cycle. #$&*your response &&&&&&&&&&&&&&&&&&
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1.5 cycles between release and second hit, and a total of 2 cycles between second and fourth hit. #$&*your response &&&&&&&&&&&&&&&&&&
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Didn't really get many measurements between fourth and sixth hit. 2 cycles between second and fourth hit, and estimated 2 cycles between fourth hit and sixth hit. #$&* Why would we expect that the time interval between release to 2d 'hit' should be shorter than the subsequent timed intervals (2d to 4th, 4th to 6th, etc.)?your response &&&&&&&&&&&&&&&&&&
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Because the cycle interval is shorter than the others. #$&* Would we expect additional subsequent time intervals to increase, decrease or stay the same?your response &&&&&&&&&&&&&&&&&&
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The intervals would decrease because the motion is slowing down. #$&*your response &&&&&&&&&&&&&&&&&&
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It does not provide much evidence to draw a good conclusion. However, the pendulum's length remained constant throughout this experiment. The angle of the pendulum may of had more effect on the outcome on the swing then the lengths. #$&* Your instructor is trying to gauge the typical time spent by students on these experiments. Please answer the following question as accurately as you can, understanding that your answer will be used only for the stated purpose and has no bearing on your grades: • Approximately how long did it take you to complete this experiment?your response &&&&&&&&&&&&&&&&&&
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#$&* *#&!Revision isn't requested, but if you do choose to submit revisions, clarifications or questions, please insert them into a copy of this document, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
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