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PHY 201
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_19.2_labelMessages **
Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
I am confused, is there a question here? I drew a vector with a force of 10 N pointing directly downward with its initial point at the origin of an x-y coordinate system.
x component = 10 N cos 250 = -3.4 N
y component = 10 N sin 250 = -9.4 N
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• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
the equilibrant x component is 3.4 N and the y component is 9.4 N.
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5 mins
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Very good responses. Let me know if you have questions.